Math 5 (9.10)
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Revision as of 12:41, 17 September 2010 by Kduncombesmith (Talk | contribs)
September test
Solve y(4)-3y(3)+5y(2)-4y'+4y=0
y=(e^2x)(ax^3+bx^2+cx+d)+fcos(x)+gsin(x)
Solve y(2)-5y(1)+6 y = c1e^-3+c2e^-2
Why, in the proof for solving diff. equations with repeated roots, can we assume that the product of f(t) with e^(r1t) is a solution? -Deanna (I don't know this answer yet.............)
Solve: y=-((yx^3+x)/3)y'-yx^2 <\br>Solution: (yx^3)/3 + yx + (x^3y^2)/6 = C
-Kelsey
