Difference between revisions of "Math 3 (9.10)"
Line 59: | Line 59: | ||
[[Math 3 (9.10)/Rohan's Question]] [[User:Rramchand|Rramchand]] 13:43, 17 September 2010 (CDT) | [[Math 3 (9.10)/Rohan's Question]] [[User:Rramchand|Rramchand]] 13:43, 17 September 2010 (CDT) | ||
+ | |||
+ | |||
+ | Find the antiderivative of (x^3)-4(x^2)+10x. | ||
+ | ANSWER: | ||
+ | (1/4)x^4 - (4/3)x^3 + 5x^2 |
Revision as of 13:45, 17 September 2010
Math 3 Notes (September 2010)
Find the derivative of the following function: h(x) = (3x^4 + 2x^3 + 5) (x^2 - 3)
ANSWER:
h'(x) = 18(x^5) + 10(x^4) -36(x^3) - 18(x^2) + 10x
--Sheinle 13:28, 17 September 2010 (CDT)
If f(x)= 2x^3-2x^2+x-1 find the zeroes, max/min, point of inflection,where the function is increasing/decreasing, and where the function is concave up/down.
Answers:
Zeroes: 1 Maximum: none Minimum: none Point of Inflection: (1/3,-22/27) Increasing: (-oo,oo) Concave up:(1/3,oo) Concave down:(-oo,1/3) --Yarefeen 13:18, 17 September 2010 (CDT)
Find the interesting stuff for the following equation:
y = (x^3) + 2(x^2) - 4x + 2
ANSWERS:
zero -3.37
max (-2, 10)
min (2/3, 14/27)
point of inflection (-2/3, 142/27)
increasing (-∞, -2) (2/3, ∞)
decreasing (-2, 2/3)
concave up (-2, ∞)
concave down (-∞, 2)--Kzhu 13:15, 17 September 2010 (CDT)
http://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/productruledirectory/ProductRule.html
Find the first derivative of the following equation:
f(x) = (x)/(x^2-4x+5)
ANSWER: f'(x) = (-x^2+5)/(x^4-8x^3+26x^2-40x+25)--Mhansen 13:36, 17 September 2010 (CDT)
Math 3 (9.10)/Rohan's Question Rramchand 13:43, 17 September 2010 (CDT)
Find the antiderivative of (x^3)-4(x^2)+10x.
ANSWER:
(1/4)x^4 - (4/3)x^3 + 5x^2