Difference between revisions of "Math 3 (9.10)"

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Find the antiderivative of (x^3)-4(x^2)+10x.
 
Find the antiderivative of (x^3)-4(x^2)+10x.
 +
 
ANSWER:
 
ANSWER:
 
(1/4)x^4 - (4/3)x^3 + 5x^2
 
(1/4)x^4 - (4/3)x^3 + 5x^2
 +
 +
--[[User:Awang|Awang]] 13:46, 17 September 2010 (CDT)

Revision as of 13:46, 17 September 2010

Math 3 Notes (September 2010)

Find the derivative of the following function: h(x) = (3x^4 + 2x^3 + 5) (x^2 - 3)


ANSWER: h'(x) = 18(x^5) + 10(x^4) -36(x^3) - 18(x^2) + 10x

--Sheinle 13:28, 17 September 2010 (CDT)


If f(x)= 2x^3-2x^2+x-1 find the zeroes, max/min, point of inflection,where the function is increasing/decreasing, and where the function is concave up/down.


Answers:

Zeroes: 1 Maximum: none Minimum: none Point of Inflection: (1/3,-22/27) Increasing: (-oo,oo) Concave up:(1/3,oo) Concave down:(-oo,1/3) --Yarefeen 13:18, 17 September 2010 (CDT)


Find the interesting stuff for the following equation:

y = (x^3) + 2(x^2) - 4x + 2


ANSWERS:

zero -3.37

max (-2, 10)

min (2/3, 14/27)

point of inflection (-2/3, 142/27)

increasing (-∞, -2) (2/3, ∞)

decreasing (-2, 2/3)

concave up (-2, ∞)

concave down (-∞, 2)--Kzhu 13:15, 17 September 2010 (CDT)

http://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/productruledirectory/ProductRule.html

Find the first derivative of the following equation:

f(x) = (x)/(x^2-4x+5)

ANSWER: f'(x) = (-x^2+5)/(x^4-8x^3+26x^2-40x+25)--Mhansen 13:36, 17 September 2010 (CDT)

Math 3 (9.10)/Rohan's Question Rramchand 13:43, 17 September 2010 (CDT)


Find the antiderivative of (x^3)-4(x^2)+10x.

ANSWER: (1/4)x^4 - (4/3)x^3 + 5x^2

--Awang 13:46, 17 September 2010 (CDT)