Difference between revisions of "Math 3 (9.10)"

From SJS Wiki
Jump to: navigation, search
Line 69: Line 69:
  
 
http://wiki.sjs.org/wiki/index.php/Math_3_(9.10)-jcowan
 
http://wiki.sjs.org/wiki/index.php/Math_3_(9.10)-jcowan
 +
 +
Why is using an antiderivative to determine the original equation of a function not accurate.
 +
 +
ANSWER:
 +
Because taking a derivative gets rid of any constants in the original equation, taking an antiderivative gives an ambiguous answer, as it can have an infinite number of possible constants added to the equation.
 +
 +
 +
----
  
  

Revision as of 14:26, 17 September 2010

Math 3 Notes (September 2010)

Find the derivative of the following function: h(x) = (3x^4 + 2x^3 + 5) (x^2 - 3)


ANSWER: h'(x) = 18(x^5) + 10(x^4) -36(x^3) - 18(x^2) + 10x

--Sheinle 13:28, 17 September 2010 (CDT)


If f(x)= 2x^3-2x^2+x-1 find the zeroes, max/min, point of inflection,where the function is increasing/decreasing, and where the function is concave up/down.


Answers:

Zeroes: 1 Maximum: none Minimum: none Point of Inflection: (1/3,-22/27) Increasing: (-oo,oo) Concave up:(1/3,oo) Concave down:(-oo,1/3) --Yarefeen 13:18, 17 September 2010 (CDT)


Find the interesting stuff for the following equation:

y = (x^3) + 2(x^2) - 4x + 2


ANSWERS:

zero -3.37

max (-2, 10)

min (2/3, 14/27)

point of inflection (-2/3, 142/27)

increasing (-∞, -2) (2/3, ∞)

decreasing (-2, 2/3)

concave up (-2, ∞)

concave down (-∞, 2)--Kzhu 13:15, 17 September 2010 (CDT)

http://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/productruledirectory/ProductRule.html

Find the first derivative of the following equation:

f(x) = (x)/(x^2-4x+5)

ANSWER: f'(x) = (-x^2+5)/(x^4-8x^3+26x^2-40x+25)--Mhansen 13:36, 17 September 2010 (CDT)

Math 3 (9.10)/Rohan's Question Rramchand 13:43, 17 September 2010 (CDT)


Find the antiderivative of (x^3)-4(x^2)+10x.

ANSWER: (1/4)x^4 - (4/3)x^3 + 5x^2

--Awang 13:46, 17 September 2010 (CDT)

http://wiki.sjs.org/wiki/index.php/Math_3_(9.10)-jcowan

Why is using an antiderivative to determine the original equation of a function not accurate.

ANSWER: Because taking a derivative gets rid of any constants in the original equation, taking an antiderivative gives an ambiguous answer, as it can have an infinite number of possible constants added to the equation.





Find the derivative for the product of these two functions: f(x)=4x^3-5 g(x)=x^3-3x

ANSWER: h'(x)=24x^5-48x^3-15x^2+15 --Areyes 14:12, 17 September 2010 (CDT)


Find the derivative of f(x)=(2x+1)/(3x^2-2)

ANSWER: f'(x)= (-6x^2-6x-4)/(9x^4-12x^2+4) --Alandrum 14:17, 17 September 2010 (CDT)